Tuesday, September 11, 2007

apptitude ques 2 (9/11)

The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in the original number, but they are in reverse order. The ten's place of the original number is equal to twice the difference between its digits. What is the number?

7 comments:

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  3. yeah sure i'll explain.... the answer is 46.....it goes like this...
    solution:
    46^2= 2116.... this is divided by half of the original num...i.e., 2116/23=92..36 is added to the quotient..so 36+92=128...the result is divided by 2.... 128/2=64....
    so the answer is the reverse of the original num... and tens place of the original num(46) is 4 and it is the twice of the differnce between the digits... 6-4=2...

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  4. i didnt get u..... tell me the forward approach..... !!!!!!!!!

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